Which Choice Below Is A Boxplot For The Following Distribution
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Mar 15, 2026 · 8 min read
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Which choice below is a boxplot for the following distribution
When you are given a data set—or a description of its shape—and several candidate boxplots, the task is to identify which graphical summary truly reflects the underlying distribution. This process combines visual intuition with a few concrete calculations: locating the median, the quartiles, the inter‑quartile range (IQR), and any potential outliers. Below is a step‑by‑step guide that walks you through the reasoning, illustrates the method with a worked example, and shows how to evaluate each option systematically. By the end, you will be able to confidently select the correct boxplot for any distribution you encounter.
Introduction: Why Matching a Boxplot Matters
A boxplot (also called a box‑and‑whisker plot) compresses a lot of information about a distribution into a compact visual: the median, the spread of the middle 50 % of the data, and the presence of extreme values. In many statistics exercises, you are presented with a numerical description (e.g., “the data are roughly symmetric with a mean of 50 and a standard deviation of 10”) or a small data set, followed by several sketch‑like boxplots labeled A, B, C, … Your job is to pick the one that best matches the given distribution.
Getting this right reinforces core concepts:
- Location – where the center of the data lies (median). * Spread – how dispersed the middle half is (IQR).
- Shape – symmetry, skewness, and tail length inferred from whisker lengths and outlier placement. * Outliers – points that fall far beyond the typical range.
Understanding how each of these features translates to the boxplot elements prevents common pitfalls, such as confusing the mean with the median or misreading whisker length as standard deviation.
Understanding the Anatomy of a Boxplot
Before diving into the selection process, let’s review the parts of a standard boxplot (Figure 1 in your mind):
| Component | What it Shows | How to Read It |
|---|---|---|
| Minimum (lower whisker end) | Smallest non‑outlier observation | Bottom of the lower whisker |
| First Quartile (Q1) | 25th percentile | Bottom edge of the box |
| Median (Q2) | 50th percentile | Line inside the box |
| Third Quartile (Q3) | 75th percentile | Top edge of the box |
| Maximum (upper whisker end) | Largest non‑outlier observation | Top of the upper whisker |
| Inter‑Quartile Range (IQR) | Q3 − Q1 | Height of the box |
| Outliers | Points beyond Q1 − 1.5·IQR or Q3 + 1.5·IQR | Individual dots or stars outside the whiskers |
| Whiskers | Extend to the most extreme non‑outlier points | Lines from the box to the min/max (or to the 1.5·IQR limits) |
A symmetric distribution yields a box with the median roughly centered and whiskers of similar length. A right‑skewed distribution shows a longer upper whisker (and possibly outliers on the high side), while a left‑skewed distribution displays the opposite pattern.
Step‑by‑Step Procedure to Identify the Correct Boxplot
Follow these five steps whenever you face a “which choice below is a boxplot for the following distribution” question.
1. Extract Key Numerical Summaries
If the problem gives you raw data, compute:
- Median – the middle value (or average of two middles).
- Q1 and Q3 – medians of the lower and upper halves.
- IQR = Q3 − Q1.
- Potential outlier boundaries: lower = Q1 − 1.5·IQR, upper = Q3 + 1.5·IQR.
If only a description is supplied (e.g., “mean = 70, median = 65, SD = 12, slight left skew”), translate those qualitative cues into approximate numbers:
- Median ≈ given median.
- Symmetry → whiskers roughly equal; skew → longer whisker on the skew side.
- Spread → IQR ≈ 1.35·SD for a normal distribution; adjust for skewness.
2. Sketch a Mental Boxplot Draw a quick schematic:
|----|=====|=====|----|
Q1 Med Q3
Place the median line, then add the box height (IQR). Extend whiskers to the calculated min and max (or to the 1.5·IQR limits if outliers exist). Mark any outliers beyond those limits.
3. Examine Each Choice Systematically
For every candidate boxplot (A, B, C, …), check:
| Checkpoint | What to Verify |
|---|---|
| Median position | Does the line inside the box sit at the approximate median value? |
| Box height | Does the distance between Q1 and Q3 match the IQR you computed? |
| Whisker lengths | Are the lower and upper whiskers roughly the lengths you expect from the min/max (or 1.5·IQR limits)? |
| Symmetry / skew | Does the relative length of whiskers reflect the described skew? |
| Outliers | Are there dots exactly where the calculated outlier boundaries predict them? |
| Scale consistency | Are the axes (if numbered) consistent with the data range? |
If a choice fails any one of these checkpoints, discard it.
4. Eliminate Distractors
Common distractors include:
- Swapping Q1 and Q3 (box upside‑down).
- Plotting the mean instead of the median.
- Making whiskers too short (ignoring the 1.5·IQR rule).
- Adding extra outliers that do not satisfy the outlier rule.
- Using a boxplot that looks like a histogram or a dot plot.
Cross‑out any option that exhibits these traits.
5. Confirm the Final Answer
After elimination, you should be left with one boxplot that satisfies all checkpoints. Double‑check by recomputing at least one feature (e.g., IQR) from the chosen boxplot and verifying it matches your earlier calculation. If it does, you have identified the correct answer.
Worked Example: Applying the Procedure
Let’s illustrate the method with a concrete data set and four candidate boxplots.
Data Set
12, 15, 18, 22, 25, 28, 30, 34, 38
**Worked Example: Applying the Procedure (continued)**
**Step 1 – Compute the five‑number summary from the data** The ordered data set is
12, 15, 18, 22, 25, 28, 30, 34, 38
* **Minimum** = 12
* **Maximum** = 38
With nine observations, the median (Q2) is the 5th value: **25**.
To find Q1 and Q3 we split the data into lower and upper halves (excluding the median because the count is odd):
* Lower half: 12, 15, 18, 22 → median of this half = (15 + 18)/2 = **16.5** → Q1 ≈ 16.5
* Upper half: 28, 30, 34, 38 → median of this half = (30 + 34)/2 = **32** → Q3 ≈ 32
* **IQR** = Q3 − Q1 = 32 − 16.5 = **15.5**
* **Outlier fences**
* Lower fence = Q1 − 1.5·IQR = 16.5 − 1.5·15.5 = 16.5 − 23.25 = **‑6.75**
* Upper fence = Q3 + 1.5·IQR = 32 + 1.5·15.5 = 32 + 23.25 = **55.25** Since the actual minimum (12) and maximum (38) lie inside these fences, there are **no outliers** in this data set.
**Step 2 – Sketch the expected boxplot**
Using the five‑number summary we anticipate:
* Box extending from Q1 = 16.5 to Q3 = 32 (height ≈ 15.5)
* Median line at 25, slightly left‑of‑center within the box (because the data are mildly right‑skewed)
* Lower whisker from 12 up to Q1 (length ≈ 4.5)
* Upper whisker from Q3 down to 38 (length ≈ 6)
* No points beyond the whiskers.
**Step 3 – Examine the four candidate boxplots**
Below are schematic descriptions of the four options (A–D). Imagine each drawn on a common horizontal axis labeled with the same scale.
| Option | Box location (Q1–Q3) | Median line | Whisker lengths | Outliers? | Comments |
|--------|----------------------|-------------|-----------------|-----------|----------|
| **A** | Q1 ≈ 15, Q3 ≈ 31 (IQR ≈ 16) | At 25 (centered) | Lower whisker to 12, upper whisker to 38 | None | Matches Q1, Q3, median, and whisker lengths within rounding; no extra points. |
| **B** | Q1 ≈ 20, Q3 ≈ 35 (IQR ≈ 15) | At 30 (too high) | Lower whisker to 12, upper whisker to 38 | None | Median is misplaced; box shifted upward. |
| **C** | Q1 ≈ 16, Q3 ≈ 33 (IQR ≈ 17) | At 25 (correct) | Lower whisker to 12, upper whisker to **50** (extends beyond upper fence) | One dot at 50 | Upper whisker too long; creates a spurious outlier. |
| **D** | Q1 ≈ 18, Q3 ≈ 30 (IQR ≈ 12) | At 25 (correct) | Lower whisker to 12, upper whisker to 38 | None | IQR too small (box too short); whiskers appear reasonable but box height inconsistent with computed IQR. |
**Step 4 – Eliminate distractors**
Continuingfrom the previous step:
**Step 4 – Confirm the correct boxplot**
After eliminating Options B, C, and D for the reasons outlined, **Option A** is the only valid representation of the data. Its box spans Q1≈15 to Q3≈31 (IQR≈16), with the median at 25, whiskers extending to the minimum (12) and maximum (38), and no outliers. This aligns perfectly with the calculated five-number summary and the absence of outliers.
**Step 5 – Final verification and interpretation**
The boxplot in Option A visually confirms the data’s distribution:
- The median line at 25 indicates the central tendency.
- The box (Q1 to Q3) spans 15 to 31, reflecting the middle 50% of the data.
- The whiskers (12 to 15 and 31 to 38) show the range of non-outlier values.
- The symmetry of the whiskers and the slight rightward skew (median closer to Q1) are consistent with the data’s mild positive skew.
This boxplot provides a clear, concise summary of the data’s spread, central tendency, and potential skewness, fulfilling the purpose of the five-number summary and outlier analysis.
---
**Conclusion**
The procedure for constructing a boxplot—calculating the five-number summary, identifying outliers, and comparing candidate plots—ensures an accurate visual representation of data distribution. In this example, the correct boxplot (Option A) was identified by rigorously verifying each step: the five-number summary (Min=12, Q1=16.5, Median=25, Q3=32, Max=38), confirming no outliers, and eliminating implausible options based on mismatched quartiles, medians, or whisker lengths. This methodical approach prevents misinterpretation and highlights the importance of precise statistical computation in data visualization. Ultimately, boxplots serve as powerful tools for summarizing data, revealing patterns, and guiding further analysis.
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