Determine If The Piecewise-defined Function Is Differentiable At The Origin

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##Determine if the piecewise-defined function is differentiable at the origin

When you are asked to determine if the piecewise-defined function is differentiable at the origin, the first thing to remember is that differentiability at a point implies continuity at that same point. In practice, a piecewise function can appear smooth on each side of the origin, but a sudden change in the formula may create a “corner” or a “cusp” that prevents the derivative from existing. In real terms, the process therefore involves two core checks: (1) confirming that the function is continuous at 0, and (2) verifying that the left‑hand derivative and the right‑hand derivative at 0 are equal. If both conditions are satisfied, the function is differentiable at the origin; otherwise it is not.

Understanding piecewise functions

A piecewise-defined function is expressed by different formulas over different intervals. As an example, a typical form is

[ f(x)=\begin{cases} f_1(x), & x<0,\[4pt] f_2(x), & x\ge 0, \end{cases} ]

where (f_1) and (f_2) may have completely different algebraic expressions. The origin ( (x=0) ) sits exactly at the boundary between the two pieces, so the definition of the function at that point must be examined carefully. The key question is whether the two “sides” meet at the same value and whether the slopes from each side agree as we approach 0.

General criteria for differentiability at a point

  1. Continuity – The limit of (f(x)) as (x) approaches 0 must equal the function’s value at 0. In symbols,

    [ \lim_{x\to 0^-} f(x)=\lim_{x\to 0^+} f(x)=f(0). ]

  2. Matching one‑sided derivatives – The derivative from the left,

    [ f'-(0)=\lim{h\to 0^-}\frac{f(0+h)-f(0)}{h}, ]

    and the derivative from the right,

    [ f'+(0)=\lim{h\to 0^+}\frac{f(0+h)-f(0)}{h}, ]

    must be identical. When these two limits exist and are equal, the function is differentiable at 0.

If either continuity fails or the one‑sided derivatives differ, the function is not differentiable at the origin The details matter here..

Step‑by‑step procedure

Below is a concise checklist you can follow for any piecewise function:

  1. Check continuity

    • Compute (\lim_{x\to 0^-} f(x)) using the formula valid for (x<0).
    • Compute (\lim_{x\to 0^+} f(x)) using the formula valid for (x\ge 0).
    • Verify that both limits are equal and that they match (f(0)).
  2. Compute the left‑hand derivative

    • Use the definition of the derivative with (h) approaching 0 from the negative side.
    • Simplify the expression and evaluate the limit.
  3. Compute the right‑hand derivative

    • Repeat the derivative definition, this time letting (h) approach 0 from the positive side.
    • Simplify and evaluate the limit.
  4. Compare the results

The analysis of differentiability at a point hinges on more than just a single calculation; it requires a careful alignment of values and slopes. When examining a function defined piecewise, ensuring continuity at the intersection point is essential, as any discontinuity would immediately disqualify differentiability. Think about it: once continuity is confirmed, the next critical step is to evaluate the derivative from both sides, confirming that these values converge to the same number. This dual verification not only solidifies the mathematical integrity of the function but also highlights the precision needed in handling abrupt changes in its structure. Now, each stage reinforces the necessity of balancing algebraic details with conceptual clarity. By systematically addressing these requirements, one gains a deeper understanding of how functions behave at boundaries. On the flip side, in practice, this process strengthens problem‑solving skills and prepares us for more complex scenarios involving higher dimensions or nonlinear transformations. The bottom line: this method provides a reliable framework for determining differentiability, ensuring accuracy and consistency throughout the evaluation. Conclusively, mastering these checks empowers us to confidently analyze functions across diverse mathematical landscapes.

To illustrate the procedure,let us examine a classic piecewise function that often serves as a litmus test for differentiability:

[ g(x)= \begin{cases} x^{2}\sin!\left(\dfrac{1}{x}\right), & x\neq 0,\[6pt] 0, & x=0. \end{cases} ]

1. Continuity check
For (x<0) and (x>0) the expression (x^{2}\sin(1/x)) is continuous, so we only need to verify the limit at the origin.

[ \lim_{x\to 0} x^{2}\sin!\left(\frac{1}{x}\right)=0, ]

because (|x^{2}\sin(1/x)|\le x^{2}) and (x^{2}\to 0) as (x\to 0). Since (g(0)=0), the function is continuous at the origin Worth knowing..

2. Left‑hand derivative

[ g'-(0)=\lim{h\to 0^-}\frac{g(0+h)-g(0)}{h} =\lim_{h\to 0^-}\frac{h^{2}\sin(1/h)}{h} =\lim_{h\to 0^-}h\sin!\left(\frac{1}{h}\right)=0, ]

because (|h\sin(1/h)|\le |h|\to 0) But it adds up..

3. Right‑hand derivative

[ g'+(0)=\lim{h\to 0^+}\frac{g(0+h)-g(0)}{h} =\lim_{h\to 0^+}h\sin!\left(\frac{1}{h}\right)=0, ]

again using the same bound. Both one‑sided limits exist and are equal, so (g) is differentiable at (0) with (g'(0)=0).

This example demonstrates that even when the underlying expression oscillates wildly, the factor (x^{2}) tames the behavior enough to permit differentiability. In contrast, consider the absolute‑value function

[ f(x)=|x|= \begin{cases} -x, & x<0,\ x, & x\ge 0. \end{cases} ]

Here continuity holds, but

[ f'-(0)=\lim{h\to 0^-}\frac{-h-0}{h}=-1,\qquad f'+(0)=\lim{h\to 0^+}\frac{h-0}{h}=1, ]

so the one‑sided derivatives differ and (f) is not differentiable at the origin Most people skip this — try not to..

4. Beyond the first derivative
When a function is differentiable at a point, we may ask whether its derivative itself is continuous there. If the derivative exists in a neighbourhood and is itself continuous, the original function is said to be (C^{1}). For the function (g) above, the derivative is

[ g'(x)= \begin{cases} 2x\sin!\left(\frac{1}{x}\right)-\cos!\left(\frac{1}{x}\right), & x\neq 0,\ 0, & x=0, \end{cases} ]

which fails to have a limit as (x\to 0) because the cosine term oscillates between (-1) and (1). So naturally, (g) is differentiable at (0) but not (C^{1}) there. This distinction becomes crucial in applications such as optimisation, where the existence of a smooth gradient guarantees the applicability of higher‑order methods.

5. Practical implications
In engineering and physics, piecewise definitions often arise from modeling different regimes (e.g., linear elasticity versus plastic deformation). Verifying continuity and matching slopes at the transition points ensures that simulated stress‑strain curves do not exhibit artificial jumps, which would otherwise lead to non‑physical predictions. Beyond that, differentiability at joining points is a prerequisite for form

calculating differential equations that govern material behavior. When numerical schemes rely on gradients, discontinuous derivatives can cause instabilities or convergence failures. Hence, engineers often smooth out sharp corners using mollifiers or spline interpolations to preserve differentiability while maintaining the essential shape of the data.

6. Generalising the construction
The technique illustrated above can be extended to build functions with prescribed smoothness properties. For any integer (n \ge 1), the function

[ h_n(x) = \begin{cases} x^n \sin(1/x), & x \neq 0,\ 0, & x = 0, \end{cases} ]

is (C^{,n-1}) at the origin but fails to be (C^n) because each differentiation reduces the power of (x) by one while introducing additional trigonometric terms. This provides a systematic way to generate counterexamples in real analysis and to test the robustness of numerical algorithms against increasingly irregular inputs Not complicated — just consistent. That's the whole idea..

7. Conclusion
The investigation of (g(x)=x^2\sin(1/x)) reveals the subtle interplay between continuity, differentiability, and smoothness. While the oscillatory factor (\sin(1/x)) might suggest pathological behavior, the polynomial prefactor (x^2) dominates near the origin, ensuring both continuity and differentiability. That said, the derivative itself inherits the wild oscillations, demonstrating that differentiability does not guarantee a continuous derivative. Understanding these distinctions is essential not only for theoretical mathematics but also for practical applications where smoothness assumptions underpin the validity of mathematical models That's the whole idea..

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